Number Theory


3 to the Power of (p-1) is not Congruent to 1 Mod P Cubed if P is Congruent to 1 Mod 6

Authors: Ramaswamy Krishnan

If\quad f(a)\quad =\quad 1\quad -\quad { a }^{ p }\quad -\quad { (1-a) }^{ p }\quad \equiv \quad 0\quad mod({ p }^{ 3 })\quad and\quad even\quad if\quad { a }^{ 2 }-a+1\quad \ncong \quad 0\quad mod(p)\\ it\quad is\quad prooved\quad that\quad f({ a }_{ r })\quad \equiv \quad 0\quad mod({ p }^{ 3 })\quad .Then\quad using\quad the\quad fact\quad that\quad if\\ { 3 }^{ p-1 }\quad \equiv \quad 1\quad mod({ p }^{ 3 })\quad ,\quad { a }^{ 2 }+a+1\quad \equiv \quad 0\quad mod({ p }^{ 3 })\quad is\quad also\quad a\quad solution\quad to\quad \\ f(a)\quad \equiv \quad 0\quad mod({ p }^{ 3 }).

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Submission history

[v1] 2017-08-17 05:25:20

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