[1] **viXra:1812.0482 [pdf]**
*submitted on 2018-12-30 19:20:53*

**Authors:** J Gregory Moxness

**Comments:** 4 Pages.

Previously, a determination of the relationship between the Natural numbers (N) and the n'th odd fibbinary number has been made using a relationship with the Golden ratio \phi=(Sqrt[5]+1}/2 and \tau=1/\phi. Specifically, if the n'th odd fibbinary equates to the j'th N, then j=Floor[n(\phi+1) - 1]. This note documents the completion of the relationship for the even fibbinary numbers, such that if the n'th even fibbinary equates to the j'th N, then j=Floor[n(\tau+1) + \tau].

**Category:** Combinatorics and Graph Theory